A = 16 days
B = 32 days
A alone worked for 10 days.
Work done by A in 10 days
=> ( 1 / 16 * 10)
=> ( 5 / 8 )
Remaining work = ( 1 -( 5 / 8))
= ( 8 - 5 ) / 8
= 3 / 8
A + B one day work
=> ( 1 /16 + 1 / 32)
=>( ( 2 + 1) / 32)
=> ( 3 / 32)
Now (3 / 32) work is done by A and B in one day
So ( 3 / 8) work will be done by A and B in ( 32 / 3) * (3 / 8)
=> 32 / 8
=> 4 days.
A 's 1 day work = 1/8
B's 1 day work = 1/12
When both work together, 1 day's work = (1/8) + (1/12) = (3+2) / 24 = 5 / 24
Number of days to complete the work will be 24 / 5 days
X's 1 day work = 1/12
Y's 1 day work = 1/42
Z's 1 day work = 1/28
All three are working together
X+Y+Z 's1 day work = (1/12) + (1/42) + (1/28)
[L C M of 12 , 42 , 28 = 84]
= (7 + 2 + 3) / 84 = 12 / 84
X+Y+Z 's 1 day work = 1/7
X+Y+Z will take 7 days to finish the work
Answer is 7
Let pipe A takes x minutes to fill cistern
The, pipe B takes 3x minutes to fill the cistern
Given, A takes 32 minutes less than B
=> Time taken by pipe A - Time taken by pipe B = 32 minutes
=> 3x - x = 32 minutes
=> x = 16 mins
=> Time taken by pipe A to fill cistern = 16 mins
Time taken by pipe B to fill cistern= 3x = 3 * 16 = 48 mins
So Time taken by both the pipe to fill cistern
= (48 x 16) / (48 + 16) minutes
= 12 minutes
Lets considers 8 days as 100 %, the work gets done So 4 days is 50 % where half of the work is done So when Arun has worked for 2 days, then => (2/8) x 100 = 100/4 = 25 %
Less men means more days ( Inverse proportion) 54 : 36 :: 18 : x => x = (36 x 18) / 54 = 36 / 3 = 12 Required number of days = 12, with 54 people working on it
16 men can complete in 8 days
1 man can do in (8 x 16) days
8 more people, now the total number of people = 8 + 16 = 24
24 men will take (8 x 16)/24 = 16/3 days
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